General Discussion

central scrutinizer

(11,667 posts) Thu Dec 26, 2019, 02:05 AM Dec 2019

For the math nerds

Suppose: y = (ln(x/m - sa))/(r^2)

Then,

yr^2 = ln(x/m - sa)

e^(yr^2) = x/m - sa

me^(rry) = x-mas

10 replies

= new reply since forum marked as read

Highlight:

For the math nerds (Original Post) central scrutinizer Dec 2019 OP

u/dgo2 tclambert Dec 2019 #1

RDRR Rstrstx Dec 2019 #2

R D R R. Igel Dec 2019 #8

Huh? PoindexterOglethorpe Dec 2019 #3

Well its obvious drray23 Dec 2019 #9

You had me at y JohnnyRingo Dec 2019 #4

Very cool! honest.abe Dec 2019 #5

x-mas is 3, why? Beacause the answer always involves the trinity. 🎄 ; 🔺 ; 👨‍👦 & 👻 TheBlackAdder Dec 2019 #6

I don't know maths but I do know a Zappa reference when I see one pecosbob Dec 2019 #7

Kick dalton99a Dec 2019 #10

tclambert

(11,087 posts)

1. u/dgo2

Reply to central scrutinizer (Original post)

Thu Dec 26, 2019, 03:19 AM

Dec 2019

u=good

Rstrstx

(1,399 posts)

2. RDRR

Reply to central scrutinizer (Original post)

Thu Dec 26, 2019, 03:20 AM

Dec 2019

This always comes to mind

Igel

(35,390 posts)

8. R D R R.

Reply to Rstrstx (Reply #2)

Thu Dec 26, 2019, 10:20 AM

Dec 2019

arg(h).

PoindexterOglethorpe

(25,929 posts)

3. Huh?

Reply to central scrutinizer (Original post)

Thu Dec 26, 2019, 03:21 AM

Dec 2019

I thought I was a math nerd but that makes no sense to me. Sigh.

I may not be as much of a math nerd as I thought I was.

Oh, wait!

Merry Christmas to you, too!

Yes, I really am a math nerd!

drray23

(7,638 posts)

9. Well its obvious

Reply to PoindexterOglethorpe (Reply #3)

Thu Dec 26, 2019, 11:34 AM

Dec 2019

Suppose: y = (ln(x/m - sa))/(r^2)

Then,

yr^2 = ln(x/m - sa)

By multiplying by r^2 both sides

e^(yr^2) = x/m - sa

By taking the exponential both sides

me^(rry) = x-mas

By replacing r^2 by rr and multiplying both sides by m and rearranging to order of variables from msa to mas.