Nikia
(1000+ posts)
Send PM |
Profile |
Ignore
|
Fri Jun-01-07 06:35 PM
Original message |
Math experts: I need your help w/ solving math problems for work |
|
I feel so like such an idiot because I know that I should be able to figure out the solution mathematically. Instead, I guess and plug numbers, wasting my time. Here is an example of a problem that I am looking to solve: I am attempting to match a formulation. The product contains (c)% of a nutrient There are two ingredients in the product. We know the usual amount of nutrient in these two ingredient. Ingredient x: (a)% nutrient Ingredient y: (b)% nutrient We know that x+y= (z)% of the total formula a+b=c We want to know what % is ingredient x and what percent is ingredient is y.
How do I solve this? I remember solving similiar problems in calculus, but that was 10 years ago and I am completely out of practice. No one at work is able or willing to help me.
I apologize for the variables. I hope that it is not too confusing. If you could explain how to solve it for me, I will be extremely greatful.
|
Nikia
(1000+ posts)
Send PM |
Profile |
Ignore
|
Fri Jun-01-07 08:53 PM
Response to Original message |
|
I know that this is kind of a heavy topic for Friday night. If this doesn't get responses, perhaps I'll PM some people who might have a better handle on this topic than me.
|
aePrime
(676 posts)
Send PM |
Profile |
Ignore
|
Fri Jun-01-07 09:47 PM
Response to Original message |
2. Hopefully I understand you correctly |
|
I'm going to use concrete numbers, because this gets rather messy symbolically.
Let's say that we know x and y make up 75% of a product (p). Let's also say that 80% of x is made up of the nutrient, and that 90% of y is made up of the nutrient. We know that the product is made up of 63% of the nutrient.
These are all of the knowns, as I understand it:
x + y = .75p .8x + .9y = .63p
Solve the first equation for x: x = .75p - y
Substitute that value for x into the second equation: .8(.75p - y) + .9y = .63p .6p - .8y + .9y = .63p .6p + .1y = .63p .1y = .03p y = .3p
We now know that y makes up 30% of the product. We can now substitute that into the first equation: x + .3p = .76p x = .45p
We now know that x makes up 45% of the product.
|
Nikia
(1000+ posts)
Send PM |
Profile |
Ignore
|
Fri Jun-01-07 10:22 PM
Response to Reply #2 |
|
When I was trying to figure it out at work, I think that I was making it more difficult than that. For some reason, I had overlooked the approach that you gave.
|
DU
AdBot (1000+ posts) |
Sun May 05th 2024, 06:41 AM
Response to Original message |