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Reply #41: No, it isn't. [View All]

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Home » Discuss » Archives » General Discussion: Presidential (Through Nov 2009) Donate to DU
Spider Jerusalem Donating Member (1000+ posts) Send PM | Profile | Ignore Tue Feb-12-08 11:52 PM
Response to Reply #39
41. No, it isn't.
It is simple mathematics. Obama leads by OVER 100 in total COMMITTED (not super) delegates. Clinton will need large margins of victory to make up the deficits...much larger margins than she can expect to win. (Even the Clinton campaign, apparently, is now admitting that a lead in total committed delegates is not likely.)

At this point, there are 1051 delegates remaining. Obama has a total (per CNN; other sources give different totals) of 1059 COMMITTED delegates, versus 956 for Hillary. If Hillary takes 50% of the remaining delegates, she still LOSES in total COMMITTED delegate count. She needs 60% or better.


You can run the numbers yourself, if you want.

And superdelegates are not committed; they can switch their votes. (Not to mention that so far, there are 398 superdelegates who have yet to commit.)
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